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| TRIM ERROR |
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| ovasquez |
 Posted: Fri Dec 28, 2007 1:30 pm Post subject: TRIM ERROR |
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Centurion
Joined: 09 Dec 2005
Posts: 141
Location: Lima, Peru
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<a>
<b> oscar <b>
<c> alex <c>
</a>
OutputRoot.MRM.a.*[I] = TRIM(BOTH ' ' from InputRoot.MRM.a.*[I+1])
in trace display: <a>oscaralex</a>...why¿?
but in:
OutputRoot.MRM.a.b = TRIM(BOTH ' ' from InputRoot.MRM.a.b)
OutputRoot.MRM.a.c = TRIM(BOTH ' ' from InputRoot.MRM.a.c)
in trace display: <a><b>oscar</b><c>alex</c></a>...why¿?
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Oscar Vásquez Flores |
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| fjb_saper |
| Posted: Fri Dec 28, 2007 1:41 pm Post subject: Re: TRIM ERROR |
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Grand High Poobah
Joined: 18 Nov 2003
Posts: 20756
Location: LI,NY
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| ovasquez wrote: |
<a>
<b> oscar <b>
<c> alex <c>
</a>
OutputRoot.MRM.a.*[I] = TRIM(BOTH ' ' from InputRoot.MRM.a.*[I+1])
in trace display: <a>oscaralex</a>...why¿?
but in:
OutputRoot.MRM.a.b = TRIM(BOTH ' ' from InputRoot.MRM.a.b)
OutputRoot.MRM.a.c = TRIM(BOTH ' ' from InputRoot.MRM.a.c)
in trace display: <a><b>oscar</b><c>alex</c></a>...why¿? |
Possible typo?
OutputRoot.MRM.a.*[I] = TRIM(BOTH ' ' from InputRoot.MRM.a.*[I])
Why the I+1 in the original??
Looks like you need some training urgently.
Message broker is not to be self taught. You will need some training...
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MQ & Broker admin |
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| ovasquez |
| Posted: Fri Dec 28, 2007 1:44 pm Post subject: |
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Centurion
Joined: 09 Dec 2005
Posts: 141
Location: Lima, Peru
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error when i writi in this forum, original source is:
OutputRoot.MRM.a.*[I] = TRIM(BOTH ' ' from InputRoot.MRM.a.*[I])
same error.
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Oscar Vásquez Flores |
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| jefflowrey |
| Posted: Sat Dec 29, 2007 6:46 am Post subject: |
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Grand Poobah
Joined: 16 Oct 2002
Posts: 19981
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I assume it's also a type on "<b> oscar <b>".
You are better to use a reference than .*[I]. There's nothing you've shown that should produce the results you have - but if you use a reference instead of *[I], you likely won't have the problem.
Edit: Hrm. Thinking about it more - unless you've created the b and c children of OutputRoot.MRM.a, then OutputRoot.MRM.a.*[i] won't point anywhere.
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