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MQSeries.net Forum Index » IBM MQ API Support » MQ 2035 Error On Discrete Connection Params

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bob8799
PostPosted: Thu Dec 11, 2008 12:48 pm    Post subject: MQ 2035 Error On Discrete Connection Params Reply with quote

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Joined: 10 Dec 2008
Posts: 13
In Windows, when I connect using the MQSERVER variable and just use...

Code:
mqQMgr = new MQQueueManager(txtMQMgr.Text);


...I can get a connection. But when I try to specify in .NET code as...

Code:
MQEnvironment.Hostname = txtMQHost.Text;
MQEnvironment.Channel = txtMQChan.Text;
MQEnvironment.Port = Convert.ToInt32("1413");
MQEnvironment.UserId = @"HTS\rhorn";
MQEnvironment.Password = "";

mqQMgr = new MQQueueManager(txtMQMgr.Text);


...I get 2035 errors. The server shows that I am passing ((None)) as the user (SID). The user on the MQ server is "rhorn". The HTS is the domain.
If I use...

Code:
MQEnvironment.UserId = "rhorn";


...I also get 2035 errors.
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bob8799
PostPosted: Thu Dec 18, 2008 12:37 pm    Post subject: Solved Reply with quote

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Joined: 10 Dec 2008
Posts: 13
What I didn't know what that using Environment.UserName overrides the MQSERVER variable. So for MQ's that use the Windows user to log in, you simply do not use the .UserID and .Password settings at all as:

Code:
'Open a connection to the MQ Mgr.
MQEnvironment.Channel = lblMQChannel.Text
MQEnvironment.Hostname = lblMQHost.Text
MQEnvironment.Port = intPort
If (strQMgr = "XXXXX" And strLoc = "YYYYY") Then
      'This overrides the MQSERVER var UserID
       MQEnvironment.UserId = USER
       MQEnvironment.Password = ""
End If


Where USER is a constant string (or passed in as a var if you wish) that contains the special user ID.
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