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MQSeries.net Forum Index » WebSphere Message Broker (ACE) Support » How to transform an XML with a return

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uliss
PostPosted: Tue Apr 17, 2007 11:17 pm    Post subject: How to transform an XML with a return Reply with quote

Apprentice

Joined: 10 Jan 2007
Posts: 27
Hi everybody,

I have a problem because I don't know how to delete a "return" from an xml message.

This is the xml tag and the data:

<DescripcionSIC>Factura con descripcion larga para detectar que problemas puede originar si el campo se informa con una longitud demasiado larga.
Probamos a informar el campo con mas de 250 caracteres para ver si da algun error de BD o si permite informarlos en SIR</DescripcionSIC>

Between the red part and the black part of the message, there is a "Return", and this is giving to me a lot of problems. Can I delete this "Return" and transform it into a "space"?

I have the 5.0.8 version of WBI

Thank you very much
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marcin.kasinski
PostPosted: Wed Apr 18, 2007 12:47 am    Post subject: Re: How to transform an XML with a return Reply with quote

Sentinel

Joined: 21 Dec 2004
Posts: 850
Location: Poland / Warsaw
I think you can do it with REPLACE ESQL function.

Try it.
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Marcin
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rajasri
PostPosted: Wed Apr 18, 2007 1:46 am    Post subject: RE Reply with quote

Centurion

Joined: 11 Jun 2006
Posts: 114
HI Uliss, did u try the suggestion of Marchin? Could you tell us what problems you are facing because of that Return.
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recallsunny
PostPosted: Wed Apr 18, 2007 1:02 pm    Post subject: Reply with quote

Disciple

Joined: 15 Jun 2005
Posts: 163
Location: Massachusetts
Code:

Unix:
Return = LineFeed  Hex'0A'

Windows:
Return = CarriageReturn+LineFeed Hex'0D0A'


Hint:
Replace the appropriate Hex bits from the Bitstream using "Replace" Function...
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