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MQSeries.net Forum IndexIBM MQ API SupportMQPMO_LOGICAL_ORDER, 2046 Return code

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Oscar
PostPosted: Mon Oct 03, 2005 2:51 pm Post subject: MQPMO_LOGICAL_ORDER, 2046 Return code Reply with quote

Newbie

Joined: 03 Oct 2005
Posts: 6

I am using VB6 to write to a queue manager on Version 5.3. I don't seem to be setting the options correctly as I always get the 2046 return code. Here's the code where I set up the Message Descriptor and the Put Message Options:

MQMsgDesc.Format = MQFMT_STRING
MQMsgDesc.Version = MQMD_VERSION_2
MQMsgDesc.MsgFlags = MQMF_MSG_IN_GROUP
MQMsgDesc.GroupId = MQGI_NONE
MQPutOpts.Version = MQPMO_CURRENT_VERSION
MQPutOpts.Options = MQPMO_LOGICAL_ORDER

Do I have to set something else up as well?
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Oscar Hopper
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fjb_saper
PostPosted: Mon Oct 03, 2005 7:29 pm Post subject: Reply with quote

Grand High Poobah

Joined: 18 Nov 2003
Posts: 20305
Location: LI,NY

Isn't LOGICAL_ORDER a GET option ??

Enjoy
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hopsala
PostPosted: Mon Oct 03, 2005 8:08 pm Post subject: Reply with quote

Guardian

Joined: 24 Sep 2004
Posts: 960

fjb_saper wrote:
Isn't LOGICAL_ORDER a GET option ??

Not exclusively. If you use MQPMO_LOGICAL_ORDER with MQPUT, MQ will set MsgSeqNumber (and Offset, if applicable) automatically to 1,2,3 etc; if you do not use it, you have to handle indexing manually.

Application Programming Guide, Chapter 10 wrote:
For example, assume that the group consists of four logical messages. The putting
application looks like this:

PMO.Options = MQPMO_LOGICAL_ORDER

MQPUT MD.MsgFlags = MQMF_MSG_IN_GROUP
MQPUT MD.MsgFlags = MQMF_MSG_IN_GROUP
MQPUT MD.MsgFlags = MQMF_MSG_IN_GROUP
MQPUT MD.MsgFlags = MQMF_LAST_MSG_IN_GROUP
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mqmhr
PostPosted: Mon Oct 03, 2005 8:13 pm Post subject: Reply with quote

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Joined: 28 Dec 2004
Posts: 105

MQPMO_LOGICAL_ORDER is a put option to specify that the message is part of a message group, whch is what Oscar is trying to do. But the null group identifier MQGI_NONE might not be a valid group identifier for a message in a group and hence this option conflicts with MQMF_MSG_IN_GROUP.

The AP Reference says that a message group is a
Quote:
...a set of one or more logical messages that have the same nonnull group identifier
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hopsala
PostPosted: Mon Oct 03, 2005 8:22 pm Post subject: Reply with quote

Guardian

Joined: 24 Sep 2004
Posts: 960

mqmhr wrote:
MQPMO_LOGICAL_ORDER is a put option to specify that the message is part of a message group, whch is what Oscar is trying to do. But the null group identifier MQGI_NONE might not be a valid group identifier for a message in a group and hence this option conflicts with MQMF_MSG_IN_GROUP.

That's incorrect - setting the groupId to NONE simply means that MQ will choose a GroupId for you, exactly as in CorrlId and MsgId; see the sample in the upcoming link.

Concerning the original poster's question - There is a sample code at the repository (MQSeries.net C/C++ repository - choose "putgroup"); a quick look shows that you didn't use "pmo.Version = MQPMO_VERSION_2;", maybe that's you're prob, but I doubt it. Please post all relevant code and we'll have a look.

(Hopefully, you didn't forget setting MQOO_OUTPUT... )
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Oscar
PostPosted: Tue Oct 04, 2005 7:13 am Post subject: My code Reply with quote

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Joined: 03 Oct 2005
Posts: 6

I have a subroutine just for PUTting the message. I make the connection and set the output type in another sub. If I remove the MQPMO_LOGICAL_ORDER, the put works.

Both messages have the same group id, but they also have the same sequence number: 1. (According to MQ Explorer) The weird part about that is, every put seems to use the same group id? Even if I close the app and restart it. Anyway, that's the second part of my issue. I just thought that MQ would automatically handle the sequencing for me.

Public Sub PutMessage(hMQConn As Long, hMQObj As Long, _
sBuffer As String, lMesgLen As Long)
Dim MQMsgDesc As MQMD ' MQ Message Descriptor
Dim MQPutOpts As MQPMO ' MQPUT Options
Dim lCompCode As Long ' Completion code
Dim lReason As Long ' Reason code
Dim sCompMsg As String ' Message to display when PUT call finished

' Set Message Descriptor to default values
MQMD_DEFAULTS MQMsgDesc

' Set PUT options to default values
MQPMO_DEFAULTS MQPutOpts

MQPutOpts.Version = MQPMO_VERSION_2
MQPutOpts.Options = MQPMO_FAIL_IF_QUIESCING + _
MQPMO_NO_SYNCPOINT + _
MQPMO_LOGICAL_ORDER

MQMsgDesc.Format = MQFMT_STRING
MQMsgDesc.Version = MQMD_VERSION_2
MQMsgDesc.MsgFlags = MQMF_MSG_IN_GROUP
MQMsgDesc.GroupId = MQGI_NONE

' PUT message to queue
MQPUT hMQConn, hMQObj, MQMsgDesc, MQPutOpts, lMesgLen, _
sBuffer, lCompCode, lReason

If lCompCode <> MQCC_OK Then
ShowMQError Trim(cmbQMgr.Text), Trim(cmbQueue.Text), _
lCompCode, lReason, "PUT # 1"
End If

MQMsgDesc.MsgFlags = MQMF_LAST_MSG_IN_GROUP

MQPUT hMQConn, hMQObj, MQMsgDesc, MQPutOpts, lMesgLen, _
sBuffer, lCompCode, lReason

If lCompCode <> MQCC_OK Then
ShowMQError Trim(cmbQMgr.Text), Trim(cmbQueue.Text), _
lCompCode, lReason, "PUT #2"
End If
End Sub
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Oscar
PostPosted: Tue Oct 04, 2005 7:56 am Post subject: Reply with quote

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Joined: 03 Oct 2005
Posts: 6

Please disregard the part about MQ using the same group id. After I had some coffee in me, I found that the group id's were different

But, I'm still getting the 2046, MQRC_OPTIONS_ERROR when I specify MQPMO_LOGICAL_ORDER.
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hopsala
PostPosted: Tue Oct 04, 2005 8:09 am Post subject: Reply with quote

Guardian

Joined: 24 Sep 2004
Posts: 960

Well, I don't see anything wrong in casual glance, and I haven't the time to start debugging your code, plus it really isn't my job look at the sample I posted and try to locate the differences...

Don't forget to post the solution when you come across it, Luck!
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Oscar
PostPosted: Tue Oct 04, 2005 9:27 am Post subject: I found it Reply with quote

Newbie

Joined: 03 Oct 2005
Posts: 6

This is a very funky problem, and I don't know if it's specific to me or not.

I set a breakpoint in the code where I set the options, and moused over each of my options to see the values:

MQPMO_FAIL_IF_QUIESCING = 8192
MQPMO_NO_SYNCPOINT = 4
MQPMO_LOGICAL_ORDER = -32768

I looked up MQPMO_LOGICAL_ORDER in the cmqb.bas, and it is defined as &H8000 (32768) ... positive. So, somewhere in my system (VB, Windows XP, the little gnomes in that box), the conversion for the logical order constants (MQGMO_LOGICAL_ORDER is defined the same way) are being incorrectly converted.

When I change the put options to:
MQPutOpts.Options = MQPMO_FAIL_IF_QUIESCING + _
MQPMO_NO_SYNCPOINT + _
32768

the program works just as I would expect it to.

Thanks to everyone who took a look and tried to help.
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PeterPotkay
PostPosted: Tue Oct 04, 2005 10:05 am Post subject: Re: I found it Reply with quote

Poobah

Joined: 15 May 2001
Posts: 7612

Oscar wrote:

MQPMO_LOGICAL_ORDER = -32768


Huh. Exactly what version of MQ are you compiling with? I know u said the QM was 5.3, but what about the libs that you are using for your app? What version, including CSD level? Maybe this is fixed in a later CSD?
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Oscar
PostPosted: Tue Oct 04, 2005 11:14 am Post subject: Reply with quote

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Joined: 03 Oct 2005
Posts: 6

I'm usind CSD09. The cmqb.bas module from the tools directory has a last modified date of 12/13/2004.

I haven't found anything on IBM's support sight that anyone else has had this problem.
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Oscar
PostPosted: Fri Oct 07, 2005 10:42 am Post subject: Reply with quote

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Joined: 03 Oct 2005
Posts: 6

I found this on a VB message board. My problem was a VB limitation. I had to change the constants to read &H8000& and everything worked. Maybe IBM should distribute the shared modules with this definition?

Anyway, the explanation:
Philip Morley <philip.morley@bmb.com.bh> wrote in message
news:39bfde9c$3@news.devx.com...
>
> Hi,
>
> The following statement in VB
> &H8000
> gives a value of -32768, when the actual value is 32768
> (8 * 16 ^3).
>
> Does anyone have any ideal why VB behaves thus.

because the value fits into a 16bit Integer field but VB interprets the high
bit as the sign bit so it becomes a negative number. Use CLNG("&H8000") or
VAL("&H8000&") in expressions or just &H8000& when used as a constant - the
trailing & forces it to be typed as a 32-bit integer.
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