Set OutputRoot.XML.(XML.ProcessingInstruction)"xml-stylesheet".(XML.Attrib)type='text/xsl';
Set OutputRoot.XML.(XML.ProcessingInstruction)"xml-stylesheet".(XML.Attrib)href='C:/stylesheetxml/applytl.xsl';
or something similar.
Unless he wants to enforce the stylesheet or make use of the stylesheet, rather than just provide the stylesheet information. _________________ I am *not* the model of the modern major general.
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