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MQSeries.net Forum Index » IBM MQ Java / JMS » Configuring MQ as an XA JMS resource

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ptazbaz
PostPosted: Thu Apr 22, 2004 4:59 pm    Post subject: Configuring MQ as an XA JMS resource Reply with quote

Apprentice

Joined: 23 May 2002
Posts: 29
Hello,

I have a question. Is there some configuration required on MQ in order to make it an XA JMS resource? I am testing with some java code and have configured the XA connection factory using JMSadmin. I continually get this error message and think it is related to something not being configured on the MQ side.

javax.jms.JMSException: MQJMS2005: failed to create MQQueueManager for 'localhost:WAL_553422'
at com.ibm.mq.jms.services.ConfigEnvironment.newException(Ljava.lang.String;Ljava.lang.Object;)Ljavax.jms.JMSException;(ConfigEnvironment.java:546)
at com.ibm.mq.jms.MQConnection.createQM()Lcom.ibm.mq.MQQueueManager;(MQConnection.java:1450)
at com.ibm.mq.jms.MQConnection.createQMXA()Lcom.ibm.mq.MQQueueManager;(MQConnection.java:915)
at com.ibm.mq.jms.MQQueueConnection.<init>(Lcom.ibm.mq.jms.MQQueueConnectionFactory;Ljava.lang.String;Ljava.lang.String;)V(MQQueueConnection.java:118)
at com.ibm.mq.jms.MQQueueConnection.<init>(Lcom.ibm.mq.jms.MQQueueConnectionFactory;)V(MQQueueConnection.java:77)
at com.ibm.mq.jms.MQXAQueueConnection.<init>(Lcom.ibm.mq.jms.MQQueueConnectionFactory;)V(MQXAQueueConnection.java:46)
at com.ibm.mq.jms.MQXAQueueConnectionFactory.createXAQueueConnection()Ljavax.jms.XAQueueConnection;(MQXAQueueConnectionFactory.java:53)
at XAQueueSendJtc.init(Ljavax.naming.Context;Ljava.lang.String;)V(XAQueueSendJtc.java:56)
at XAQueueSendJtc.main([Ljava.lang.String;)V(XAQueueSendJtc.java:110)

This same question applies to creating topics as well. I have some sample Java code and created a MQTopicFactory using JmsAdmin and am getting an error message as well. I think I have to make some MQ settings in order to resolve both of these problems. Any input or confirmation is much appreciated. Thanks.

-Paul
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bower5932
PostPosted: Fri Apr 23, 2004 5:44 am    Post subject: Reply with quote

Jedi Knight

Joined: 27 Aug 2001
Posts: 3023
Location: Dallas, TX, USA
Get the linked exception:
Code:

 } catch( JMSException je ) {                               
     System.out.println("JMS Exception: " + je);             
     // check for a linked exception                         
     Exception le = je.getLinkedException();                 
     if (le != null) {                                       
        System.out.println("Linked exception: " + le);       
     }                                                       
                                                             
  }                                                         

It will shed more light on what is happening.
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