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MQSeries.net Forum Index » WebSphere Message Broker (ACE) Support » Copying part of MRM-XML input to XML output

Copying part of MRM-XML input to XML output

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vmcgloin

Posted: Tue Oct 07, 2003 1:36 am Post subject: Copying part of MRM-XML input to XML output

Knight

Joined: 04 Apr 2002
Posts: 560
Location: Scotland

Hi,

I have an input message that is parsed by the MRM. I want to copy part of that message to the output as XML (not MRM-XML). However, I could do with some advice on how to do this. I have tried several methods but not all the subfields are being copied.

The relevant part of the input message (from a trace node) is:

Code:

(0x100001B)MRM = (
...
(0x1000013)MailMessage = (
(0x300000B)MailTo = 'vmcgloin@xyz.co.uk'
(0x300000B)MailFrom = 'abc@xyz.co.uk'
(0x300000B)MailSubject = 'This is a sample message'
(0x1000013)MailBody = (
(0x200000B) = 'This is a sample message body'
)
)
...

I have tried:

Code:

SET "OutputRoot"."XML"."MailMessage" = InputRoot.MRM."MailMessage";

which produces this output (losing the MailBody information)

Code:

(0x1000010)XML = (
(0x1000000)MailMessage = (
(0x1000000)MailTo = (
(0x2000000) = 'vmcgloin@xyz.co.uk'
)
(0x1000000)MailFrom = (
(0x2000000) = 'abc@xyz.co.uk'
)
(0x1000000)MailSubject = (
(0x2000000) = 'This is a sample message'
)
(0x1000000)MailBody =
)
)

and, based on the copying of message headers,

Code:

SET C = CARDINALITY(InputRoot.MRM."MailMessage".*[]);
SET I = 1;
WHILE I < C DO
SET OutputRoot."XML"."MailMessage".*[I] = InputRoot.MRM."MailMessage".*[I];
SET I=I+1;
END WHILE;

which produces this output (losing the MailBody tag and data):

Code:

Sorry for the long post, but I am new to this kind of stuff and would appreciate any pointers in the right direction...

Thanks,
Vicky

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