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How to get independent replies from Aggregate Reply node? |
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eai143 |
Posted: Mon Jul 11, 2011 2:48 am Post subject: How to get independent replies from Aggregate Reply node? |
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Apprentice
Joined: 16 Aug 2006 Posts: 28
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Hi All,
In my flow, From Aggregate Control node, I'm sending the input msg to 2(say Student and Employee) different compute nodes and from there to corresponding separate message flows.
Say there is some failure in Employee flow. and we are not getting the reply from Employee flow.
In the reply flow, at Aggregate Reply node, after the timeout, Can I get the Student reply separately? Is there any way to get the independent replies? |
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paintpot |
Posted: Mon Jul 11, 2011 3:01 am Post subject: |
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Centurion
Joined: 19 Sep 2005 Posts: 112 Location: UK
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Yes, you will get the data from your successful Student call on your Timeout message - it is up to you how you decide to proceed from there. |
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eai143 |
Posted: Mon Jul 11, 2011 3:07 am Post subject: |
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Apprentice
Joined: 16 Aug 2006 Posts: 28
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Hi Paintpot,
thanks for the quick response.
What happens if both the messages fail in their corresponding message flows? As no message will come to aggregate reply node, will the control pass to timeout terminal? |
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smdavies99 |
Posted: Mon Jul 11, 2011 3:43 am Post subject: |
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 Jedi Council
Joined: 10 Feb 2003 Posts: 6076 Location: Somewhere over the Rainbow this side of Never-never land.
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eai143 wrote: |
Hi Paintpot,
thanks for the quick response.
What happens if both the messages fail in their corresponding message flows? As no message will come to aggregate reply node, will the control pass to timeout terminal? |
Isn't is easy to try this for yourself? _________________ WMQ User since 1999
MQSI/WBI/WMB/'Thingy' User since 2002
Linux user since 1995
Every time you reinvent the wheel the more square it gets (anon). If in doubt think and investigate before you ask silly questions. |
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paintpot |
Posted: Mon Jul 11, 2011 3:53 am Post subject: |
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Centurion
Joined: 19 Sep 2005 Posts: 112 Location: UK
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I agree -
it is good to test almost every combination yourself, as otherwise it is easy to get confused - highly recommended to take the whole apart conceptually and prove the combinations |
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