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XML 101

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Posted: Wed Apr 23, 2003 7:52 am Post subject: XML 101

Padawan

Joined: 27 Mar 2003
Posts: 1564
Location: Hartford, CT.

I have an elementary XML question. After a successful LDAP lookup the results returned look something like this:

(0x1000000)XML = (
(0x1000000)LDAP = (
(0x1000000)Results = (
(0x1000000)Entry = (
(0x1000000)givenName = (
(0x1000000)Value = (
(0x2000000) = 'John'
)
)
(0x1000000)cn = (
(0x1000000)Value = (
(0x2000000) = 'John L. Doe'
)
(0x1000000)Value = (
(0x2000000) = 'JLDOE'
)
)
(0x1000000)sn = (
(0x1000000)Value = (
(0x2000000) = 'Doe'
)
)
(0x1000000)uid = (
(0x1000000)Value = (
(0x2000000) = 'JLDOE'
)
)
(0x1000000)createTimestamp = (
(0x1000000)Value = (
(0x2000000) = '20021203133517Z'
)
)
)
)
)
)

How do I reference the value for the XML tags "cn" & "uid"? I've attempted the following with no success:

Code:

SET OutputRoot.XML.ldapResults.displayName = InputRoot.XML.LDAP.Results.Entry.cn.Value[1];
SET OutputRoot.XML.ldapResults.networkId = InputRoot.XML.LDAP.Results.Entry.uid.Value;

I've also tried:

Code:

SET OutputRoot.XML.ldapResults.displayName = InputRoot.XML.LDAP.Results.Entry.cn.[XML.Content];
SET OutputRoot.XML.ldapResults.networkId = InputRoot.XML.LDAP.Results.Entry.uid.[XML.Content];

Any assistance would be greatly appreciated.

RamVijayawada

Posted: Wed Apr 23, 2003 9:25 am Post subject:

Novice

Joined: 22 Apr 2003
Posts: 15

Have u tried this?
InputBody.XML.LDAP.Results.Entry.cn.Value;
If not can u post the whole XML Structure....

ernest-ter.kuile

Posted: Mon Apr 28, 2003 10:13 am Post subject: Re: XML 101

Apprentice

Joined: 13 May 2002
Posts: 49
Location: KLM Holland

I think you had the index at the wrong place. It's cn that has more than one value, not cn.value

try this :

Code:

InputRoot.XML.LDAP.Results.Entry.cn[1].Value;

should do the trick for cn for the first Value.

Code:

InputRoot.XML.LDAP.Results.Entry.uid.Value;

for the uid.

and the XML.Content isn't really necessary, but should be between () not []. like this :

Code:

InputRoot.XML.LDAP.Results.Entry.cn[1].Value.(XML.Content);

Have fun.

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