Posted: Tue Apr 08, 2003 11:51 am Post subject: Creating an indexed field?
Master
Joined: 21 Nov 2002 Posts: 200
HI! I have to create a tag that has two indexes. I am getting an eror with the following code: Can someone help me understand what I am doing wrong? Thanks!! LisaB
CREATE FIELD OutputRoot.XML.ChangeJob.DataArea.Job.ExternalNumbers;
CREATE FIELD OutputRoot.XML.ChangeJob.DataArea.Job.ExternalNumbers.ExternalNumber[1];
SET OutputRoot.XML.ChangeJob.DataArea.Job.ExternalNumbers.ExternalNumber[1].
(XML.Attribute)index=1;
CREATE FIELD OutputRoot.XML.ChangeJob.DataArea.Job.ExternalNumbers.ExternalNumber[2];
SET OutputRoot.XML.ChangeJob.DataArea.Job.ExternalNumbers.ExternalNumber[2].
(XML.Attribute)index=2;
SET OutputRoot.XML.ChangeJob.DataArea.Job.ExternalNumbers.ExternalNumber[2] =
InputRoot.XML.ATLAS_XY_QUERY.DataArea.RECORD_DATA.EXTERNAL_TWO;
Joined: 05 Sep 2001 Posts: 3779 Location: Torrance, CA, USA
Use this instead:
Code:
SET OutputRoot.XML.ChangeJob.DataArea.Job.ExternalNumbers.ExternalNumber[1].(XML.Attribute)index=1;
SET OutputRoot.XML.ChangeJob.DataArea.Job.ExternalNumbers.ExternalNumber[2].(XML.Attribute)index=2;
SET OutputRoot.XML.ChangeJob.DataArea.Job.ExternalNumbers.ExternalNumber[2] = InputRoot.XML.ATLAS_XY_QUERY.DataArea.RECORD_DATA.EXTERNAL_TWO;
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