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RocknRambo
PostPosted: Mon Aug 16, 2004 7:48 am    Post subject: carrying on the elements Reply with quote

Partisan

Joined: 24 Sep 2003
Posts: 355

hi everybody....

my input message is a XML...with some 10 elements... and I need to send to the output queue, the whole message just adding 3 more elements under the same root tree..

so what I'm doing..is..... just using the code..

SET InputRoot = OutputRoot;
then map the extra 3 elements which I need to map.

but what I see in the output Queue is...two root elements. (the same ones)

or do I need to map the whole elements again.

can anybody suggest on this.

thanks in advance
sanu.
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JT
PostPosted: Mon Aug 16, 2004 8:02 am    Post subject: Reply with quote

Padawan

Joined: 27 Mar 2003
Posts: 1564
Location: Hartford, CT.

Please show us your ESQL code as the following statement is not corrrect:
Code:
SET InputRoot = OutputRoot

I assume this is a 'typo' and you intended:
Code:
SET OutputRoot = InputRoot;
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RocknRambo
PostPosted: Mon Aug 16, 2004 9:01 am    Post subject: Reply with quote

Partisan

Joined: 24 Sep 2003
Posts: 355

hi JT....

you r right....that was typo.

sanu.
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EddieA
PostPosted: Mon Aug 16, 2004 9:08 am    Post subject: Reply with quote

Jedi

Joined: 28 Jun 2001
Posts: 2453
Location: Los Angeles

Quote:
Please show us your ESQL code

Cheers,
_________________
Eddie Atherton
IBM Certified Solution Developer - WebSphere Message Broker V6.1
IBM Certified Solution Developer - WebSphere Message Broker V7.0
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RocknRambo
PostPosted: Mon Aug 16, 2004 4:51 pm    Post subject: Reply with quote

Partisan

Joined: 24 Sep 2003
Posts: 355

Thank u guys.....

I donno it worked wierd...like the same code...after recycling the broker...it worked fine..


sanu.
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